Calculer, développer  les expressions A et B pour      x= -1                                                                    
   A= (x+3)²- (3-x)²                   et B= 2x +3                                                        
                                                          x - 2                                                                                    


Sagot :

A= (x+3)²-(3-x)²
  =(-1+3)²-(3-(-1))²
   = 2²-4²=4-16=-12
B = 2x+3/x-2
   =-2+3/-1-2
   =1/-3=-1/3
A= (x+3)²- (3-x)² 
A= (-1+3)²-(3+1)²
A= 4-16
A= -12

B=[tex] \frac{2x+3}{x-2} = \frac{-2+3}{-1-2} = \frac{1}{-3} =- \frac{1}{3} [/tex]