Sagot :
A= (x+3)²-(3-x)²
=(-1+3)²-(3-(-1))²
= 2²-4²=4-16=-12
B = 2x+3/x-2
=-2+3/-1-2
=1/-3=-1/3
=(-1+3)²-(3-(-1))²
= 2²-4²=4-16=-12
B = 2x+3/x-2
=-2+3/-1-2
=1/-3=-1/3
A= (x+3)²- (3-x)²
A= (-1+3)²-(3+1)²
A= 4-16
A= -12
B=[tex] \frac{2x+3}{x-2} = \frac{-2+3}{-1-2} = \frac{1}{-3} =- \frac{1}{3} [/tex]
A= (-1+3)²-(3+1)²
A= 4-16
A= -12
B=[tex] \frac{2x+3}{x-2} = \frac{-2+3}{-1-2} = \frac{1}{-3} =- \frac{1}{3} [/tex]