Answered

j'ai besoin de factoriser 2x²-8x
(5x-1)(x+1)-3(5x-1)
x²+4x+4
(x+5)²-4x²
Merci d'avance pour votre aide ;)

Sagot :

2x²-8x
=(2x)(x-4)

(5x-1)(x+1)-3(5x-1)
=(5x-1)(x+1-3)
=(5x-1)(x-2)

x²+4x+4
=(x+2)²

(x+5)²-4x²
=(x+5-2x)(x+5+2x)
=(-x+5)(3x+5)
2x^2 - 8X= x(2X-8)
(5x-1)(x+1)-3(5x-1) = (5x-1)(x-2)
x²+4x+4= (x+2)^2
(x+5)²-4x² = (5x+5)(-3x+5)