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Sagot :

(5x-8)(x-3)-(x+1)(x-3)=0
(x-3)(5x-8)-(x+1) = 0
(x-3)(5x-8-x-1) =0
(x-3)(4x -9) = 0
soit x-3 = 0 et x = 3
soit 4x-9 = 0 et 4x = 9 d'où x = 9/4


(5x-8)-(x-3)-(x+1)-(x-3)=0

(x-3)(5x-8)-(x+1) = 0
(x-3)(5x-8-x-1) = 0
(x-3)(4x-9) = 0
résolu précedemment

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