Answered

Bonsoir, factoriser a (x)=(x+3)^2-9(x-1)^2
Trouver forme canonique et factoriser de f (x)=3x^2-13x+14
Merci d'avance.

Sagot :

f(x)=(x+3)²-9(x-1)²
    =(x+3-3(x-1))(x+3+3('x-1))
    =(x+3-3x+3)(x+3+3x-3)
    =(-2x+6)(4x)
    =(8x)(3-x)


f(x)=3x²-13x+14
     =3(x²-13/3x)+14
     =3((x-13/6)²-169/36)+14
     =3(x-13/6)²-1/12