Bonjour,
Factoriser: (2x+5)(2x-3)+(x-2)(2x-3)+4x²-9 = (2x-3)(6x-6) ?
= (2x + 5)(2x - 3) + (x - 2)(2x - 3) + (2x - 3)(2x + 3)
= (2x - 3)(2x + 5 + x - 2 + 2x + 3)
= (2x - 3)(5x + 6)
Factoriser: (5x+1)²-(3x+4)² = (2x-3)(8x+5) ?
= (5x + 1 - 3x - 4)(5x + 1 + 3x + 4)
= (2x - 3)(8x + 5)
Et pour m'aider à :
Factoriser: (4x-6)(x-3)-(2x-3)²-10x²+15x
= 2(2x - 3)(x - 3) - (2x - 3)² - 5x(2x - 3)
= (2x - 3)[2(x - 3) - 2x + 3 - 5x)
= (2x - 3)(2x - 6 - 7x + 3)
= (2x - 3)(-5x - 3)
Developper: 2x+5)(2x-3)+(x-2)(2x-3)+4x²-9
= 2x * 2x + 2x * -3 + 5 * 2x + 5 * -3 + x * 2x + x * -3 - 2 * 2x - 2 * -3 + 4x² - 9
= 4x² - 6x + 10x - 15 + 2x² - 3x - 4x + 6 + 4x² - 9
= 10x² - 3x - 18
Developper: (5x+1)²-(3x+4)²
= 25x² + 10x + 1 - 9x² - 24x - 16
= 16x² - 14x - 15
Developper: (4x-6)(x-3)-(2x-3)²-10x²+15x
= 4x² - 12x - 6x + 18 - 4x² + 12x - 9 - 10x² + 15x
= -10x² + 9x + 9
